## Determine the peak value of the applied voltage and the current if the ac source is to deliver the same power to the load.

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The 120-V dc source of Fig. 1(a) delivers 3.6 W to the load. Determine the peak value of the applied voltage (Em) and the current (Im) if the ac source Fig. 1(b) is to deliver the same power to the load.   realnfo
2021-10-29 12:50:43
$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$
$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$ realnfo
2021-10-29 12:59:39
$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$
$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$ realnfo
2021-10-29 13:02:11
$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$
$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$ realnfo
2021-10-29 13:06:19