Find the voltage across and charge on capacitor.

408 Views Posted: 2 years
Solved, Closed

Find the voltage across and charge on capacitor C1 of the network shown in the figure below after it has charged up to its final value.

2021-07-24 15:44:03
1 Answer
As we already know that capacitor is effectively an open circuit for dc sources after charging up to its final value. The network can be redrawn as by removing capacitor from its branch assuming capacitor act as an open circuit.
$$\begin{split}V_C &= {R_2 \, E \over R_2 + R_1}\\&= {8 \times 24 \over 8 + 4}\\&= 16 V \end{split}$$

$$\begin{split} Q_1 &= C_1 \, V_C\\&= (20\times 10^{-6})(16V)\\&= 320 \mu F\\\end{split}$$

2021-07-25 08:48:47

Do you want to say or ask something?

Only 250 characters are allowed. Remaining: 250
Please login to enter your comments. Login or Signup .
Be the first to comment here!
Terms and Condition
Copyright © 2011 - 2024
Privacy Policy