Before examining the application
of the method to ac networks, the student should first review the appropriate sections on mesh analysis in Chapter 7 since the content of this
section will be limited to the general conclusions of
Chapter 7.
The general approach to mesh analysis for independent sources
includes the same sequence of steps appearing in Chapter 8. In fact,
throughout this section the only change from the dc coverage will be to
substitute impedance for resistance and admittance for conductance in
the general procedure.
- Assign a distinct current in the clockwise direction to each
independent closed loop of the network. It is not absolutely
necessary to choose the clockwise direction for each loop current.
However, it eliminates the need to have to choose a direction for
each application. Any direction can be chosen for each loop
current with no loss in accuracy as long as the remaining steps are
followed properly.
- Indicate the polarities within each loop for each impedance as
determined by the assumed direction of loop current for that loop.
- Apply Kirchhoff's voltage law around each closed loop in the
clockwise direction. Again, the clockwise direction was chosen to
establish uniformity and to prepare us for the format approach to
follow.
- If an impedance has two or more assumed currents through it,
the total current through the impedance is the assumed current
of the loop in which Kirchhoff's voltage law is being applied,
plus the assumed currents of the other loops passing through in
the same direction, minus the assumed currents passing
through in the opposite direction.
- The polarity of a voltage source is unaffected by the direction of
the assigned loop currents.
- Solve the resulting simultaneous linear equations for the assumed
loop currents.
The technique is applied as above for all networks with independent
sources or for networks with dependent sources where the controlling
variable is not a part of the network under investigation. If the controlling variable is part of the network being examined, a method to be
described shortly must be applied.
Example 1: find the
current $I_1$ in Fig. 1 using mesh analysis.
Fig. 1: Example 1.
Solution:
When applying these methods to ac circuits, it is good
practice to represent the resistors and reactances (or combinations
thereof) by subscripted impedances. When the total solution is found in
terms of these subscripted impedances, the numerical values can be
substituted to find the unknown quantities.
Fig. 2: Assigning the mesh currents and subscripted
impedances for the network of Fig. 1.
The network is redrawn in Fig. 2 with subscripted impedances:
$$Z_1 = j X_L =j 2 Ω \,\, E_1 = 2 V \angle 0^\circ$$
$$Z_2 = R = 4Ω \,\, E_2 =6 V \angle 0^\circ$$
$$Z_3 = - j X_C = - j 1 Ω $$
step 3:
$$ \begin{split}
+E_1 - I_1Z_1 - Z_2(I_1 - I_2) &= 0\\
-Z_2(I_2 - I_1) - I_2 Z_3 - E_2 &=0\\
\text{or}\\
E_1 - I_1Z_1 -I_1Z_2 + I_2Z_2 &=0\\
-I_2Z_2 + I_1Z_2 - I_2Z_3 - E_2 &=0\\
\text{so that}\\
I_1(Z_1 + Z_2) - I_2 Z_2 &=E_1\\
I_2(Z_2 + Z_3) - I_1 Z_2 &= -E_2\\
\text{which are rewritten as}\\
I_1(Z_1 + Z_2) - I_2 Z_2 &=E_1\\
- I_1 Z_2 + I_2(Z_2 + Z_3) &= -E_2\\
\end{split}
$$
using determinants, we obtain
$$
\Delta = \begin{vmatrix}
Z_1 + Z_2 & -Z_2 \\
-Z_2 & Z_2 + Z_3
\end{vmatrix}
$$
$$\begin{gather}
I_1 = {
\begin{vmatrix}
E_1 & -Z_2 \\
-E_2 & Z_2+Z_3 \\
\end{vmatrix}
\over \Delta}\\
I_1 = 3.61 A \angle -236.30^\circ\\
\end{gather}
$$
Example 2: Write the mesh currents for the network of Fig. 3
having a dependent voltage source.
Fig. 3: Applying mesh analysis to a network with a
voltage-controlled voltage source.
Solution:
$$ \begin{gather}
E_1 - I_1 R_1 - R_2 (I_1 - I_2) = 0\\
R_2 (I_2 - I_1) + \mu V_x - I_2R_3 = 0\\
\text{then substitute}\, V_x = (I_1 - I_2)R_2\\
R_2 (I_2 - I_1) + \mu [(I_1 - I_2)R_2] - I_2R_3 = 0\\
\text{The result is two equations and two unknowns.}\\
(R_1+R_2)I_1 - I_2R_2 = - E_1 \tag{1}\\
(\mu R_2 - R_2)I_1 +(R_2 - \mu R_2 - R_3)I_2 = 0 \tag{2}\\
\end{gather}
$$
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